Organic Chemistry I · Lesson 08

Substitution

In a substitution reaction, a nucleophile comes in and a leaving group goes out. There are two ways it happens: SN2 in one concerted step, and SN1 through a carbocation. The whole skill here is reading the conditions and predicting which one you will get.

Learning Goals

  • Describe the general pattern of a nucleophilic substitution reaction.
  • Explain what the 1 and 2 in SN1 and SN2 actually mean.
  • Classify alkyl halides as methyl, primary, secondary, or tertiary.
  • Rank carbocation stability and explain why tertiary is most stable.
  • Draw the SN2 mechanism and predict inversion of configuration.
  • Explain what makes a strong nucleophile and rank nucleophilicity.
  • Draw the SN1 mechanism through its carbocation intermediate.
  • Identify good and bad leaving groups.
  • Choose SN1 or SN2 from the substrate, nucleophile, solvent, and leaving group.

Key Terms

Tap any term to see its definition.

Section 1

What Is Substitution?

A substitution reaction is exactly what it sounds like: one group leaves and another takes its place. The general pattern is R-LG + Nu⁻ → R-Nu + LG⁻.

The general substitution pattern showing a nucleophile replacing a leaving group on a carbon

Nucleophile in, leaving group out

Here is the textbook example. CH₃Br + OH⁻ → CH₃OH + Br⁻. Bromide is the leaving group, hydroxide is the nucleophile, and OH ends up where Br used to be.

Methyl bromide reacting with hydroxide to give methanol and bromide

CH₃Br + OH⁻ → CH₃OH + Br⁻

The one-liner I want you to keep

Substitution = nucleophile in, leaving group out. Everything else in this lesson is just figuring out the timing of those two events.

Section 2

What Does SN Mean?

Let me break the name down properly, because the label tells you almost everything. SN stands for nucleophilic substitution: the S is substitution, the N is nucleophilic. Then the number: SN1 is unimolecular nucleophilic substitution, and SN2 is bimolecular nucleophilic substitution.

What the number really means

The number does not count steps. It counts how many species are involved in the rate-determining step. That single idea is the thing most students get wrong, so I want it nailed down before we go any further.

Setup

Alkyl Halides and Carbocation Stability

Before we split into SN1 and SN2, you need two quick tools, because the rest of the lesson leans on them constantly. The first is classifying the substrate. An alkyl halide is a carbon bonded to a halogen, and we label that carbon by how many other carbons are attached to it: methyl (zero), primary (one), secondary (two), or tertiary (three).

Methyl, primary, secondary, and tertiary alkyl halides shown side by side with the attached carbons counted

Methyl, primary, secondary, tertiary

The second tool is carbocation stability, and this is the one I really want you to understand rather than memorize. A carbocation is an electron-poor carbon with a positive charge. Anything that donates electron density toward that carbon stabilizes it. Alkyl groups do exactly that, through hyperconjugation (donation from neighboring C-H and C-C bonds) and a small inductive push. So the more alkyl groups attached, the more stable the cation.

Carbocation stability ranked tertiary greater than secondary greater than primary greater than methyl

Tertiary > secondary > primary > methyl

Neighboring C-H bonds donating electron density into an empty carbocation orbital

Hyperconjugation stabilizes the positive charge

Why I am front-loading this

Hold onto one ranking: tertiary > secondary > primary > methyl for carbocation stability. SN1 lives and dies by it, because SN1 has to form a carbocation. Keep this in your back pocket for the SN1 sections coming up.

Section 3

What SN2 Really Means

SN2 is one-step substitution. The nucleophile attacks at the exact same time the leaving group leaves, so two things are involved in that single slow step: the substrate and the nucleophile. That is why the rate law is rate = k[substrate][nucleophile].

That rate law tells you what speeds SN2 up. A stronger or more concentrated nucleophile makes it faster. A better leaving group makes it easier. And less steric hindrance makes it easier, because the nucleophile needs room to get in.

SN2 in one phrase

SN2 = nucleophile attacks while the leaving group leaves. One smooth, concerted motion, no intermediate in between.

Section 4

The SN2 Mechanism

The key to the whole mechanism is backside attack. The nucleophile comes in from the side directly opposite the leaving group, because that is where it can reach the antibonding orbital of the C-LG bond.

An SN2 reaction with the nucleophile attacking from the side opposite the leaving group in one concerted step

Backside attack, opposite the leaving group

Because the nucleophile comes in from the back, the carbon flips. This gives inversion of configuration, like an umbrella turning inside out in the wind. If you tracked stereochemistry in Lesson 6, this is where it starts paying off.

A stereocenter inverting during SN2, illustrated as an umbrella flipping inside out

Inversion: the umbrella flips

Section 5

What Favors SN2

Three conditions decide whether SN2 is happy. Here is how I check each one.

Substrate

methyl > primary > secondary, and tertiary is essentially blocked. The less crowded the carbon, the easier the backside attack.

Nucleophile

Needs a strong nucleophile. Good choices include OH⁻, RO⁻, CN⁻, N₃⁻, I⁻, Br⁻, and HS⁻. Weak nucleophiles slow SN2 down.

Solvent

Favored by polar aprotic solvents such as DMSO, DMF, acetone, and acetonitrile, because they do not trap the nucleophile.

Substrate reactivity for SN2 ranked methyl greater than primary greater than secondary, with tertiary blocked

SN2 substrate: methyl > primary > secondary, tertiary blocked

Going deeper

What Actually Makes a Good Nucleophile

I keep saying SN2 wants a strong nucleophile, so let me tell you what strong actually means. Nucleophilicity is just how readily a species donates its electrons to form a new bond. The rule underneath everything: the more available the electrons, the more nucleophilic the species. So the first thing I do is find the nucleophilic center, usually a lone pair or an anion, and then ask how freely those electrons are willing to move.

Three trends tell you almost everything, and two of them line up with basicity while the third does not.

Across a row

Nucleophilicity falls left to right, so C⁻ > N⁻ > O⁻ > F⁻. Rising electronegativity holds the lone pair tighter and makes it less available. This matches the basicity order.

Same atom, more charge

For the same central atom, more electron density means a better nucleophile, so HO⁻ > H₂O. An anion always beats its neutral version. This also matches basicity.

Down a group

Nucleophilicity rises down a group, so I⁻ > Br⁻ > Cl⁻ > F⁻. Bigger atoms are more polarizable, and that loosely held electron density reaches out to form the new bond more easily. This is the opposite of the basicity order.

Nucleophilicity trends across a row, for increasing charge on the same atom, and down a group

The three nucleophilicity trends

The trend I want you to remember most

Down a group, nucleophilicity and basicity go opposite ways. I⁻ is a weaker base than F⁻ but a far better nucleophile, because a big, polarizable iodide reaches out to form the new C-X bond much more easily. Polarizability barely helps basicity, since a proton is tiny, but it matters a lot for attacking carbon.

And here is a working ranking of common nucleophiles, roughly strongest to weakest, so you have something concrete to reach for.

StrengthNucleophiles
Very goodI⁻, HS⁻, RS⁻
GoodBr⁻, HO⁻, RO⁻, CN⁻, N₃⁻
ModerateNH₃, Cl⁻, F⁻, RCO₂⁻
WeakH₂O, ROH
Very weakRCO₂H

The SN2 recipe

SN2 = strong nucleophile + good leaving group + low steric hindrance. If all three line up, SN2 is your reaction.

Section 6

What SN1 Really Means

SN1 is two-step substitution. First the leaving group leaves, then the nucleophile attacks. The slow step is only the substrate losing its leaving group, so the rate law is rate = k[substrate]. The nucleophile is nowhere in that rate-determining step.

That is the whole reason SN1 can run with a weak nucleophile. If the nucleophile is not in the slow step, it does not need to be strong to get the job done.

SN1 in one phrase

SN1 = leaving group leaves first to form a carbocation, then the nucleophile attacks. The substrate sets the pace all by itself.

Section 7

The SN1 Mechanism

The SN1 mechanism runs in two or three moves. Step one: the leaving group leaves and a carbocation forms. Step two: the nucleophile attacks the carbocation. Step three, only if needed: a quick deprotonation cleans up the charge to give a neutral product.

The SN1 mechanism showing the leaving group leaving to form a carbocation, then the nucleophile attacking

Leaving group leaves, carbocation forms, nucleophile attacks

That carbocation is the whole catch. SN1 only works if the carbocation is reasonably stable, which is exactly why the stability ranking from the setup section matters so much here.

A flat carbocation being attacked from both faces to give a racemic mixture

A flat carbocation gets attacked from either face

Why SN1 scrambles stereochemistry

The carbocation is flat, so the nucleophile can come in from either face. That is why SN1 tends to give racemization, a mixture, rather than the clean inversion you get from SN2.

Section 8

What Favors SN1

The same three conditions, read the opposite way from SN2.

Substrate

tertiary > secondary, and primary or methyl are essentially out, because their carbocations are too unstable to form.

Nucleophile

Can be weak, like H₂O or ROH, because the nucleophile is not in the rate-determining step.

Solvent

Favored by polar protic solvents such as water, methanol, and ethanol, because they stabilize ions and help the leaving group leave.

Substrate reactivity for SN1 ranked tertiary greater than secondary, with primary and methyl ruled out

SN1 substrate: tertiary > secondary, primary and methyl out

The SN1 recipe

SN1 = stable carbocation + good leaving group + often a weak nucleophile and a polar protic solvent. The substrate carries the reaction, so it has to be able to form that cation.

Section 9

Leaving Groups

Neither pathway works without a good leaving group, so this section matters for both. A good leaving group is stable after it leaves, which usually means it is a weak base.

Good leaving groups

I⁻Br⁻Cl⁻TosylateMesylateWater (after OH is protonated)

Among the halides, the ranking is I⁻ > Br⁻ > Cl⁻.

Bad leaving groups

OH⁻NH₂⁻RO⁻H⁻

These are strong bases, so they hold their electrons too tightly to leave easily.

Leaving group ability ranked from iodide down through the strong-base poor leaving groups

Stable, weak bases leave best

The alcohol trap

OH is a bad leaving group unless you protonate it first. That is why alcohols usually need acid before substitution: protonating the OH turns it into water, which leaves easily. I always check for this whenever I see an alcohol as the substrate.

An alcohol OH being protonated to water so it can act as a good leaving group

Protonate OH to make it a good leaving group

Section 10

SN1 vs SN2 Side by Side

This is the table I want you able to reproduce from memory by the end of the lesson.

FeatureSN1SN2
StepsTwo stepsOne step
Rate lawk[substrate]k[substrate][nucleophile]
NucleophileCan be weakUsually strong
Best substrateTertiaryMethyl / primary
Carbocation?YesNo
Rearrangements?PossibleNo
StereochemistryRacemization / mixtureInversion
SolventPolar proticPolar aprotic

Section 11

The Decision System

When you are handed a reaction and asked which pathway it takes, run these four questions in this order. This is the exact sequence I use every time.

1

What is the substrate?

Methyl or primary points to SN2. Tertiary points to SN1. Secondary is the middle ground and depends on the nucleophile and solvent.

2

Is the nucleophile strong?

A strong nucleophile favors SN2. A weak nucleophile favors SN1, as long as the carbocation would be stable enough to form.

3

Is the solvent protic or aprotic?

Polar aprotic favors SN2. Polar protic favors SN1.

4

Is the leaving group good?

No good leaving group means no good substitution, either way. Check this before you trust any other answer.

A flowchart deciding between SN1 and SN2 based on substrate, nucleophile, solvent, and leaving group

SN1 vs SN2 decision flowchart

The cleanest summary I can give you

SN2 = strong Nu + good LG + low steric hindrance. SN1 = stable carbocation + good LG + often a weak Nu and a protic solvent. Memorize those two lines and the decision system mostly runs itself.

Common Mistakes

Watch Out for These

Reading the 1 and 2 as the number of steps. They count the species in the rate-determining step, not the steps.
Trying to run SN2 on a tertiary substrate. It is too crowded for backside attack.
Trying to run SN1 on a methyl or primary substrate. Those carbocations are too unstable to form.
Forgetting that SN2 gives inversion, while SN1 gives a mixture from a flat carbocation.
Using a weak nucleophile and expecting fast SN2.
Treating OH as a leaving group without protonating it first. Neutral OH⁻ is a poor leaving group.
Swapping the solvents: SN2 wants polar aprotic, SN1 wants polar protic.
Ignoring the leaving group entirely. No good leaving group means no good substitution.

Practice Set

Try each question before opening the answer.

1. What does the general substitution pattern look like?

Answer: R-LG + Nu⁻ → R-Nu + LG⁻. A nucleophile comes in and a leaving group goes out, on the same carbon.

2. What do the 1 and 2 in SN1 and SN2 actually count?

Answer: The number of species involved in the rate-determining step. SN1 involves one (the substrate), SN2 involves two (the substrate and the nucleophile).

3. Why does SN2 fail on tertiary substrates?

Answer: SN2 needs a backside attack opposite the leaving group, and a tertiary carbon is too crowded for the nucleophile to reach that position.

4. Rank carbocation stability: methyl, primary, secondary, tertiary.

Answer: Tertiary > secondary > primary > methyl. More attached alkyl groups donate more electron density through hyperconjugation and induction, stabilizing the positive charge.

5. What stereochemical outcome does SN2 give, and why?

Answer: Inversion of configuration. The nucleophile attacks from the side opposite the leaving group, flipping the center like an umbrella turning inside out.

6. Why can SN1 proceed with a weak nucleophile?

Answer: Because the nucleophile is not part of the rate-determining step. The slow step is just the leaving group departing to form the carbocation, so even a weak nucleophile can finish the job afterward.

7. Why does SN1 often give racemization?

Answer: The carbocation intermediate is flat (trigonal planar), so the nucleophile can attack either face roughly equally, producing a mixture of stereochemical outcomes.

8. Which solvent favors SN2, and which favors SN1?

Answer: Polar aprotic (DMSO, DMF, acetone, acetonitrile) favors SN2 by keeping the nucleophile reactive. Polar protic (water, methanol, ethanol) favors SN1 by stabilizing ions.

9. Why do alcohols often need acid before they can undergo substitution?

Answer: OH⁻ is a poor leaving group. Protonating the OH turns it into water, which is a good leaving group, so the substitution can proceed.

10. A secondary substrate reacts with a strong nucleophile in DMSO. SN1 or SN2?

Answer: SN2. A secondary substrate can go either way, but a strong nucleophile in a polar aprotic solvent tips it firmly toward SN2.

Ready for a bigger set?

Work through the full Substitution practice page: classifying substrates, ranking carbocations and leaving groups, predicting SN1 vs SN2 from conditions, and calling the stereochemical outcome.

Do Substitution Practice

Lesson Summary

Substitution swaps a nucleophile in for a leaving group. The number in SN1 and SN2 counts species in the rate-determining step, not the number of steps. SN2 is one concerted step with a backside attack that gives inversion, and it wants a strong nucleophile, a methyl or primary substrate, and a polar aprotic solvent. SN1 forms a carbocation first (so it needs a stable one, tertiary > secondary > primary > methyl), tolerates a weak nucleophile, prefers a polar protic solvent, and gives racemization. Both need a good leaving group. To call a reaction, walk the substrate, then the nucleophile, then the solvent, then the leaving group.